T Distribution Calculator
The t distribution calculator makes it easy to compute the cumulative probability associated with a t score or with a sample mean. For help in using the calculator, read the FrequentlyAsked Questions or review the Sample Problems.
To learn more about Student's t distribution, go to Stat Trek's tutorial on the t distribution.
Note: Both the t distribution and the normal distribution assume that observations are normally distributed in the population. And as sample size increases, the t distribution becomes increasingly similar to the normal distribution. So when would a researcher choose the t distribution over the normal distribution? A common rule of thumb is to choose the t distribution when (1) the sample size is small and/or (2) the population standard deviation is unknown.
FrequentlyAsked Questions
Instructions: To find the answer to a frequentlyasked question, simply click on the question.
Which statistic should I use  the t score or the mean score"?
The t distribution calculator accepts two statistics as input: a t score or a sample mean. Choose the option that is easiest. Here are some things to consider.

If you choose to work with t statistics, you may need to transform your raw
data into a t statistic. You can accomplish this transformation by using the
following equation:
t = [ x  μ ] / [ s / sqrt( n ) ]
where x is the sample mean, μ is the population mean, s is the standard deviation of the sample, n is the sample size, and t is the t statistic.  If you choose to work with the sample mean, you can avoid the "transformation" step. But you will need to provide additional input in the form of the population mean and/or the sample standard deviation.
For an example that uses the t score, see Sample Problem 1. For an example that uses the sample mean, see Sample Problem 2
What are degrees of freedom?
Degrees of freedom can be described as the number of scores that are free to vary. For example, suppose you tossed three dice. The total score adds up to 12. If you rolled a 3 on the first die and a 5 on the second, then you know that the third die must be a 4 (otherwise, the total would not add up to 12). In this example, 2 die are free to vary while the third is not. Therefore, there are 2 degrees of freedom.
In many situations, the degrees of freedom are equal to the number of observations minus one. Thus, if the sample size were 20, there would be 20 observations; and the degrees of freedom would be 20 minus 1 or 19.
What is a standard deviation?
The standard deviation is a numerical value used to indicate how widely individuals in a group vary. It is a measure of the average distance of individual observations from the group mean.
What is a t statistic?
A t statistic is a statistic whose values are given by
t = [ x  μ> ] / [ s / sqrt( n ) ]
where x is the sample mean, μ is the population mean, s is the standard deviation of the sample, n is the sample size, and t is the t statistic.
What is a population mean?
A mean score is an average score. It is the sum of individual scores divided by the number of individuals. A population mean is the mean score of a population.
What is a sample mean?
A mean score is an average score. It is the sum of individual scores divided by the number of individuals. A sample mean is the mean score of a sample.
What is a probability?
A probability is a number expressing the chances that a specific event will occur. This number can take on any value from 0 to 1. A probability of 0 means that there is zero chance that the event will occur; a probability of 1 means that the event is certain to occur. Numbers between 0 and 1 quantify the uncertainty associated with the event. For example, the probability of a coin flip resulting in Heads (rather than Tails) would be 0.50. Fifty percent of the time, the coin flip would result in Heads; and fifty percent of the time, it would result in Tails.
What is a cumulative probability?
A cumulative probability is a sum of probabilities. In connection with the t distribution calculator, a cumulative probability refers to the probability that a t score or a raw score will be less than or equal to a specified value.
Suppose, for example, that we sample 100 firstgraders. If we ask about the probability that the average first grader weighs exactly 70 pounds, we are asking about a simple probability  not a cumulative probability.
But if we ask about the probability that average weight is less than or equal to 70 pounds, we are really asking about a sum of probabilities (i.e., the probability that the average weight is exactly 70 pounds plus the probability that it is 69 pounds plus the probability that it is 68 pounds, etc.). Thus, we are asking about a cumulative probability.
Note: The t distribution calculator only reports cumulative probabilities (e.g., the probability that a t score is less than or equal to a specified value.)
Sample Problems

The Acme Chain Company claims that their chains have an average breaking
strength of 20,000 pounds, with a standard deviation of 1750 pounds. Suppose a customer
buys 14 randomlyselected chains. What is the probability that the average breaking strength
for the customer's' chains will be 19,800 pounds or less?
Solution:
One strategy would be a twostep approach:
 Compute a t statistic, assuming that the breaking strength for the customer's chains is 19,800 pounds.
 Determine the cumulative probability for that t statistic.
We will follow that strategy here. First, we compute the t statistic:
t = [ x  μ ] / [ s / sqrt( n ) ]
t = (19,800  20,000) / [ 1750 / sqrt(14) ]
t = ( 200 ) / [ (1750) / (3.74166) ]
t = ( 200 ) / (467.707) = 0.4276
where x is the mean breaking stength in the customer's chains, μ is the population mean, s is the standard deviation, n is the sample size, and t is the t statistic.
Now, we can determine the cumulative probability for the t statistic. We know the following:
 The t statistic is equal to 0.4276.
 The number of degrees of freedom is equal to 13. (In situations like this, the number of degrees of freedom is equal to number of observations minus 1. Hence, the number of degrees of freedom is equal to 14  1 or 13.)
Now, we are ready to use the T Distribution Calculator. Since we have already computed the t statistic, we select "t score" from the dropdown box. Then, we enter the t statistic (0.4276) and the degrees of freedom (13) into the calculator, and hit the Calculate button. The calculator reports that the cumulative probability is 0.338.
Therefore, there is a 33.8% chance that the average breaking strength for the customer's chains will be no more than 19,800 pounds.
Note: The strategy that we used required us to first compute a t statistic, and then use the T Distribution Calculator to find the cumulative probability. An alternative strategy, which does not require us to compute a t statistic, would be to use the calculator in the "mean score" mode. That strategy may be a little bit easier. It is illustrated in the next example.

Let's look one more time at the problem that we addressed above in
Example 1. This time, we will illustrate a different, easier strategy to solve
the problem.
Here, once again, is the problem: The Acme Chain Company claims that their chains have an average breaking strength of 20,000 pounds, with a standard deviation of 1750 pounds. A customer buys 14 randomlyselected chains. What is the probability that the average breaking strength for the customer's chains will be no more than 19,800 pounds?
Solution:
We know the following:
 The population mean is 20,000.
 The standard deviation is 1750.
 The sample mean, for which we want to find a cumulative probability, is 19,800.
 The number of degrees of freedom is 13. (In situations like this, the number of degrees of freedom is equal to number of observations minus 1. Hence, the number of degrees of freedom is equal to 14  1 or 13.)
First, we select "mean score" from the dropdown box in the T Distribution Calculator. Then, we plug our known inputs (degrees of freedom, sample mean, standard deviation, and population mean) into the T Distribution Calculator and hit the Calculate button. The calculator reports that the cumulative probability is 0.338. Thus, there is a 33.8% probability that the average breaking strength for the customer's chains will be 19,800 pounds or less.
Note: This is the same answer that we found in Example 1. However, the approach that we followed in this example may be a little bit easier than the approach that we used in the previous example, since this approach does not require manual computation of a t statistic.
 The principal at a local high school claims that the average IQ of his faculty is higher
than the actual IQ of 90% of teachers in the district.
The school board administered an IQ test to 15 randomly selected teachers at a his high school. They
found that the average IQ score was 115 with a standard deviation of 11. Assume that the principal's
claim about his faculty is correct. What would be the average IQ of a teacher in the district?
Note: In terms of cumulative probability, the notion that 90% of teachers in the district have an IQ of 115 or less implies that P(IQ≤115) is 0.90.
Solution:
We know the following:
 The cumulative probability is 0.90.
 The standard deviation is 11.
 The sample mean is 115.
 The number of degrees of freedom is 14. (In situations like this, the number of degrees of freedom is equal to number of observations minus 1. Hence, the number of degrees of freedom is equal to 15  1 or 14.)
First, we select "mean score" from the dropdown box in the T Distribution Calculator. Then, we plug the known inputs (cumulative probability, standard deviation, sample mean, and degrees of freedom) into the calculator and hit the Calculate button. The calculator reports that the population mean is 111.2.
Thus, if the principal's assessment of the IQ of his faculty is correct, we conclude that the average IQ of a teacher in the district is 111.2.